Give the first and last names of the staff.
select first_name, last_name from staff
Also list the date of birth.
select first_name, last_name, date_of_birth from staff
What is the birthday of the staff member with first name as Janessa and last name as Sawayn?
select date_of_birth from staff where first_name = "Janessa" and last_name = "Sawayn";