how many address are presented on the table
select count ( * ) from addresses
list out the staff first name on the table
select first_name from staff
what is the city of Janessa
select t1.city from addresses as t1 join staff as t2 on t1.address_id = t2.staff_address_id where t2.first_name = "Janessa"
exactly
select * from addresses as t1 join staff as t2 on t1.address_id = t2.staff_address_id where t2.first_name = "Kaitlin"