give me the organization id then
select t1.organisation_id from projects as t1 join project_outcomes as t2 on t1.project_id = t2.project_id group by t1.organisation_id order by count ( * ) desc limit 1
give me its project details.
select t1.organisation_id, t1.project_details from projects as t1 join project_outcomes as t2 on t1.project_id = t2.project_id group by t1.organisation_id order by count ( * ) desc limit 1
for `deleniti
select t2.outcome_code from projects as t1 join project_outcomes as t2 on t1.project_id = t2.project_id where t1.project_details = "deleniti"